gemmated 的音標為[?d?embme?t?d]，基本翻譯為“結合的，合并的”。速記技巧可以考慮使用發音相似的單詞或字母組合來幫助記憶。例如，可以將 gemmated 拆分為 gem 和 mate 兩個單詞，這樣就可以聯想到“gem”是寶石的意思，“mate”是伴侶的意思，結合起來就是“寶石伴侶”，從而幫助記憶 gemmated 這個單詞。

Gemmate的英文詞源是“gemma”，意為“寶石”或“結晶體”。這個詞來源于拉丁語，意為“寶石”或“結晶”。Gemmate這個詞在英語中通常指兩個或多個晶體之間的連接或結合。

變化形式：geminate，由gemma派生而來，意為“復數”或“復音的”。

相關單詞：

1. gemination：復音形成，復數產生。

2. geminationist：復數形成專家。

3. geminationism：復數形成的方法或理論。

4. geminate：復數的，復音的。

5. gemination-related：與復數形成相關的。

6. gemmule：寶石般的物質，復數形式的胚胎。

7. gemmulate：寶石般的，復數形式的。

8. gemmulate-related：與寶石般的物質相關的。

9. gemmulate-like：類似于寶石般的物質。

10. gemmulate-like structure：類似于寶石般的結構。

Gemmate這個詞在生物學和地質學中也有應用，特別是在描述植物和動物的復數生殖以及晶體之間的連接。這些單詞反映了gemmate這個詞在各個領域中的廣泛應用和演變。

常用短語：

1. multiply together

2. add up

3. add up to

4. multiply by

5. add up to a sum

6. multiply matrices

7. add vectors

雙語例句：

1. Multiply matrices A and B to get the result C. (矩陣A和B相乘得到結果C)

2. The sum of the numbers equals to 5. (這些數字的和等于5)

3. Adding vectors a and b gives c. (向量a和b的和是c)

4. Multiply a by b and you get c. (乘以b得到c)

5. The product of two numbers is 3. (兩個數的乘積是3)

6. Adding up the numbers in column A, we get the total in column B. (在列A中加總，得到列B的總和)

7. Multiply A and B and you will get the result C. (乘以A和B，你將得到結果C)

英文小作文：

Today, we are going to discuss the basic operations of matrix multiplication and addition, which are essential for many mathematical problems in science and engineering. Matrix multiplication is a way to combine two matrices into a new matrix, which can be thought of as multiplying each element of one matrix by each element of another matrix. This operation is widely used in linear algebra, optimization, and other fields of mathematics. On the other hand, matrix addition is a way to combine two matrices by adding their corresponding elements together. This operation is also very useful in many practical problems. In addition, vector addition is another fundamental operation that we need to understand when dealing with mathematical problems involving vectors. These operations are fundamental to many scientific and engineering problems, and it is essential to understand them well in order to solve these problems effectively.